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In this paper different Vedic mathematics methods explained also its applications which are used for the difference in competition observations for any quality example of a learner. This paper is about of old Vedic mathematics nothing like it methods looking upon multiplications 1, number system, algebra using values no higher than squared equations 2 also boat able to go underwater topics divisibility rules& simple-making and so on.
In different in competition observations, these topics are included which destruct much time than ready (to be used) time, given Vedic mathematics ways of doing& its applications helps to get the answer to problems in less time with accurately 3& affect on.
In today's order of events, every parent wants their children person having especially great powers of mind, quick& very good, of the highest quality in the direction of the complete learned in theory living.
However they all while seeming in the in-competition observations, they get an unsuccessful person mostly in mathematics subjects that are reasoning things talked of.
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“ Writer-marian did a very good job with my paper, she got straight to the point, she made it clear and organized ”
This Vedic mathematics paper will give them hope& secret that they can get done their uncontrolled thoughts in sleep by using Vedic mathematics in their observations. Some of the applications of Vedic mathematics techniques are made, be moving in this paper.
Vedic Mathematics consists of 16 Sutras or Word Formulae and 13 sub-sutras (Sub Formulae) which can be used for solving mathematical problems in a far simpler manner. It offers techniques and shortcuts to master numerical calculations in split seconds. Using these techniques, it is possible to calculate 10-15 times faster than usual methods.
The difficult problems or huge sums can be solved almost immediately by the Vedic method. In the race of competition and the technology, we left behind the importance of the traditional methods, which were once originated years ago to help us in solving the complexity of the mathematics problems in algebra. With the increase in the cutthroat competition of the ambitious exams, most of the aspirants stuck in quantitative part just because of long calculations.
The competitive exams like SSC, IBPS, RRB and UPSC, comprises of the Maths section. So, if you are planning to appear in any of these exams then, this article will really help you out in the calculations. Here, you will get to know the VedicMaths tricks to solve the quantitative part. After learning the VedicMaths practices you can easily solve the complex problems with speed and accuracy.
The reference number should be shown in square bracket [1]. However the authors name can be used along with the reference number in the running text. The order of reference in the running text should match with the list of references at the end of the paper.
Here, some vedic mathematics methods are described which helps students to reduce their calculation time and improve their accuracy.
In mathematics trigonometry is the heart, we can find Pythagoras triplates of any even and odd number.
there are 3 simple steps, 1st we have to square it, 2nd divide it by 2 and third and final step is 1 time add 0.5 and substract 0.5 from the number. Simple that’s the answer !!! Ex: 3 ---> Squaring it ---> 9 Divide it by 2 ---> 4.5 ---> add 0.5 and substract 0.5 in it ---> we got 4 and 5 two numbers so, our Pythagorean triplates are 3,4 and 5. We can use these technique for any odd numbers.
the same procedure we are using here but in 4 simple steps. But 1st step we have to divide the even number by 2 until the number gets odd. And the same constant we have to multiply in final triplates. Another procedure is same as above.
so 1st we have divide the even number until it gets odd. 2nd square it, 3nd divide it by 2 and forth and final step is 1 time add +0.5 and substract -0.5 from the number. Simple that’s the answer !!! Ex: 14 ---> Divide it by 2 untill it gets odd. So, 7 ---> now Squaring it ---> 49 Divide it by 2 ---> 24.5 ---> add 0.5 and substract 0.5 in it ---> we got 24 and 25 two numbers. so, our Pythagorean triplates are 7,24 and 25. Now multiply it by constant by 2 because we divide it initially. So, our finalytriplates are 14,24 nad 50. We can use these technique for any Even numbers.
After standerd 7th , major in 8th , 9th and 10th Trigonometry sums we can see, even in competitive examinations like railways we can see examples of trigonometry. One of the example is If SinA = (4/5), then find the value of tan2A = (?) it is very difficult and lengthy sums it is. In vedic mathematics it is very easy. In these types of sums we can find any of the ratio like tan2A, cot2A, sec2A, cosec2A etc. we can find triplates from sine equation, that is a=3,b=4 and c=5. Now, put these value in ( ( / 2ab / ) put the value of a,b and c here we got 7,24 and 25. So, Sin2A = (7/25), cos2A = (24/25), tan2A = (7/24) so, simple as that we can find all the other ratios similarly for an example,
Ex: SinA = (3/5) then find the value of cot(A/2) = (?).
for half of the ratio the equations are ((a+c)/ b /)
So, we get 8, 4 and 4. and that’s all now we get all the half ratio, Sin(A/2) = (), cos(A/2) = (1/), tan(A/2) = (2). So, these two are the best trigonometry time saving method.
In Various competitive examinations this is ever green topic.
Railway, SSC and any other state level examination ask quadratic equations in 2 to 4 marks. Here are the very short tricks to solve any of the equations in 5 to 6 seconds only. We just put direct answers to the equations. For an
example : to solve this equations we have to remember a table of sign. Now for both (-ve) sign
Value of x will be in one (+ve) & one (-ve). Now do the part of 10 like the subtraction of the factors will be negative 3. And that’s all. Divide it with the coefficient of x2. So here in this case X = ) and X = . So these is how we can direct calculate the answers of quardetic equations possible outcome.
For any of the linear equations for an example:
2x + 4y = 10 , 3x + 2y = 11
We know usually students take 2 to 3 minutes to solve any linear equations. Here I explained a awesome shortcut method without any formula to answer the value of X and Y. Here, we all know that coefficient of a1,b1,c1 and a2,b2,c2 so to find out the value of X we can do a cross multiplication, so, the value we got x = by putting the value in equations we can find out the value of y also these same methods we can use in boat and stream sums mostly asked in examinations. In standard 10th textbook these types of sums given in example.
Ex: a boat goes 2km upstream and 4 km downstream in 6 hr also 3km upstream and 2km downstream in 7 hr. so calculate the speed of boat and stream.
In these types of sums we can assume U = and D = , where U = Upstream and D = Downstream. So, the linear equation we made is,
2U + 4D = 6
3U + 2D = 7
as per the above cross tricks we can direct calculate value of U=2 and D=1 and find the value of Boat and Stream as 1.25 and 0.75 Km/hr. So, for linear equations this the best method to calculate and find the value of x and y.
Simplification is the advance arithmetic topic comes under various examinations of 3 to 4 marks that are for sure. It requires accuracy and presence of mind elsewhere the answer goes wrong cut the marks which leads far from our government job goals.
For an Example: 1071225 is a perfect square root or not ? Do we have a perfect method to calculate this mcq within 20 seconds ? No!! but vedicmaths has. And that is as follow, 1st apply the digit sum method 1+0+7+1+2+2+5 = 9 so it’s a perfect square if the digit sum gives 2/3/5/6/8 then it is non perfect square root and others are perfect square root. Also if the unit place is 2/3/7/8 then also non perfect square roots. So these are the identities of non perfect square roots. And we can answer the question. Now how to do square root so, that’s the basic method introduce in vedicmaths that we all know.
Another tricks as follow for an example :
Which digit should be added to the number 5167340 so it is perfectly divisible by 13 ?
So, in these type of questions we know how big division it is and how time consuming it is one simple trick is there by the grace of vedic mathematics and that is as follow: key of 13, Substract the last 3 digit number from the remaining numbers if the answer is divisible by 13 then the number is also divisible by 13.
So, 5167-340=4827, repeated 827-4=823 but dividing 823 with 13 we get 4 as a reminder so 4 is the number we can add to the number 5167340+4=5167344 to perfectly divisible it by 13. Woo !!!!! Practice this tricks we can do in normally 15 to 20 seconds easily.
Similarly we can apply these tricks with 17/19 also. We can easily calculate the number is divisible by 17 or 19 or not.
Other lots of vedic mathematics tricks which are used in normal aptitude calculations includes vertically crosswise method, base multiplication, nikhilam division method, dwandh square and cube methods. One of them special multiplication method is : multiply with 101 we got the number two times.
for an example : 33*101=3333 / 98*101=9898 any three digit number like 132*101 so we have to just add 1 in 132 = 133 and other number are same that is 32. So the answer is 13332. Similarly the number in between 200 to 300 add 2 and so on. For an example : 565*101=57065.
Square root of the Complex numbers :
If we want to do square root Z = it seems very difficult to do square root and we don’t have a proper method to do a square root. In vedic mathematics the method is as follow: if the final square of Z is then a = , b = y/2a and r = mode Z that’s it now put the value and get the answers.
For an Ex: Z = 12+5i then as per above equations,
r = = 13
a = , also b = y/2a = and our Final answer is + )
We know the square root of these equations or complex numbers are very difficult and students can skip this types of questions due to the phobia of square root / complex numbers / mathematics equations. This method will help students to build their confidence towards mathematics develop an interest and hope in their mind that mathematics is a simple calculations with interest.
Here very few topics regarding time saving methods in Aptitude originally comes from the Vedic mathematics are discussed. A small push to help students and small effort to use Vedic mathematics in different mathematical chapters. From the above Vedic mathematics tricks the person preparing/appearing in the various competitive examinations can able to reduce the calculation time helps him/her to go more towards Vedic mathematics and learn the ancient mathematics of India.
Applications of Vedic Mathematics in Various Competitive Examinations. (2024, Feb 15). Retrieved from https://studymoose.com/document/applications-of-vedic-mathematics-in-various-competitive-examinations
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