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Esterification is a chemical reaction involving the reaction of a carboxylic acid with an alcohol. In this experiment, we carried out the esterification reaction between ethanoic acid and propan-1-ol, resulting in the formation of propyl ethanoate and water. The equilibrium constant (Kc) of the reaction was determined to be 7.74. The addition of concentrated sulphuric(VI) acid acted as a catalyst to accelerate the reaction. The experiment involved titration with sodium hydroxide to analyze the equilibrium mixtures.
Esterification is a fundamental chemical reaction that involves the formation of an ester from a carboxylic acid and an alcohol.
In this experiment, we focused on the esterification of ethanoic acid (CH3COOH) and propan-1-ol (CH3CH2CH2OH). The chemical reaction can be represented as follows:
CH3COOH(aq) + CH3CH2CH2OH(aq) → CH3COOCH2CH2CH3(aq) + H2O(l)
This reaction is known to be relatively slow at room temperature, allowing for the study of its equilibrium and the determination of the equilibrium constant (Kc).
The equilibrium constant is a crucial parameter that characterizes the extent of a chemical reaction at equilibrium.
Because this is a homogeneous reaction with the same number of moles of reactants and products, the stability continuous (Kc) is generally expressed in regards to molarity or can be computed in regards to moles alone which is more hassle-free. Since the reaction is extremely sluggish at room temperature level, it is accelerated by addition of driver (concentrated sulphuric(VI) acid ). But the catalyst does not take part in the overall response.
The analysis of the equilibrium mixes is based on a simple titration with standardized NaOH.
Given that the preliminary quantities of all materials are understood and the overall changes in the response can be shown by the decision of the last amount of acid. The concentrated H2SO4 catalyst stays the same and when a quantity of acid is deducted out, there is only ethanoic acid. If less acid is discovered than initial addition, the response has moved in the forward instructions. If more acid is spotted, the response has actually relocated the reverse direction. Given that the stoichiometric ratios in the reaction are all unity, the loss or gain in ethanoic acid can be utilized to figure the loss or gain in whatever else.
During the titration, the reaction mixture changed from colorless to red.
Titration | Final Burette Reading (cm3) | Initial Burette Reading (cm3) | Volume of Titre (cm3) |
---|---|---|---|
1 | 22.00 | 2.90 | 19.10 |
2 | 41.50 | 22.00 | 19.50 |
3 | 6.55 | 0.85 | 5.70 |
4 | 12.00 | 6.55 | 5.45 |
Volume of sodium hydroxide required for neutralizing concentrated sulphuric(VI) acid = V2 - V1 = 19.50 cm3 - 19.10 cm3 = 0.40 cm3
Volume of sodium hydroxide required for neutralizing the remaining ethanoic acid after refluxing for 30 minutes = V3 - (V2 - V1) = 5.70 cm3 - 0.40 cm3 = 5.30 cm3
Volume of sodium hydroxide required for neutralizing the remaining ethanoic acid after refluxing for 50 minutes = V4 - (V2 - V1) = 5.45 cm3 - 0.40 cm3 = 5.05 cm3
The equilibrium constant (Kc) for the esterification reaction between ethanoic acid and propan-1-ol was determined to be 7.74. This value signifies the extent of the reaction at equilibrium. The addition of concentrated sulphuric(VI) acid acted as a catalyst, expediting the reaction without being consumed. The experiment employed titration with sodium hydroxide to analyze the equilibrium mixtures and calculate the concentration of reactants and products.
Future experiments could explore the effects of different reaction conditions, such as temperature and catalyst concentration, on the esterification reaction. Additionally, further studies could investigate the applications of esters in various industries, including the fragrance and flavor industry.
Experiment Report: Esterification of Ethanoic Acid and Propan-1-ol. (2017, Aug 10). Retrieved from https://studymoose.com/document/determination-of-the-equilibrium-constant-for-esterification
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