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The purpose of this experiment is to become familiar with the use of the general pan balance and the "weigh by balance" method for determining the density of compounds, as well as to determine the precise operation of a pipette. Additionally, this experiment aims to illustrate the mole method, density calculations, dimensional analysis, and the evaluation of deviation and errors in measurements.
Throughout the experiment, the following equations are used:
Experiment A1 was completed exactly as described in Chemistry 217 Home Laboratory Manual, pp. 72-76, with no deviations from the prescribed procedure.
Measurement | Value |
---|---|
Mass of vial + carbon | 6.31 g |
Mass of empty vial | 4.55 g |
Mass of carbon transferred to beaker | 1.00 g |
Mass of vial + tin | 21.80 g |
Mass of empty vial | 9.80 g |
Mass of tin transferred to beaker | 1.02 g |
Calculations:
1.00 g / 12.01 g/mol = 0.083 mol C (amount of moles of C transferred to beaker)
0.083 mol C x 6.022 x 1023 atoms/mol = 0.50 x 1023 atoms of C (number of C atoms transferred to beaker)
1.02 g / 118.71 g/mol = 0.0086 mol Tin (amount of moles of Tin transferred to beaker)
0.0086 mol Tin x 6.022 x 1023 atoms/mol = 0.52 x 1023 atoms of Tin (number of Tin atoms transferred to beaker)
Results:
1.00 g C / 0.50 x 1023 atom of C = 2.00 x 10-23 g
1.02 g tin / 0.52 x 1023 atom of tin = 1.96 x 10-23 g
1.96 x 10-23 g / 2.00 x 10-23 g = 0.98:1
9.983:1
Measurement | Value |
---|---|
Volume of water in cylinder | 25 mL |
Mass of water + cylinder | 52.26 g |
Mass of empty cylinder | 29.18 g |
Mass of water in cylinder | 23.08 g |
Water temperature | 25˚C |
Calculations:
23.08 g / 25 mL = 0.9232 g/mL
Literature value for density of water at 25˚C: 0.99707 g/mL (as per Chemistry 217 Home Laboratory Manual, pp. 65)
# | Mass Beaker + Water | Mass Empty Beaker | Mass of Water | Temperature of Water | Density of Water at 25˚C | Volume of Water Dispensed (ml) |
---|---|---|---|---|---|---|
1 | 34.12 g | 29.18 g | 4.94 g | 25˚C | 0.99707 g/mL | 4.9545 mL |
2 | 34.09 g | 29.18 g | 4.91 g | 25˚C | 0.99707 g/mL | 4.9244 mL |
3 | 34.12 g | 29.18 g | 4.94 g | 25˚C | 0.99707 g/mL | 4.9545 mL |
4 | 34.11 g | 29.18 g | 4.93 g | 25˚C | 0.99707 g/mL | 4.9444 mL |
5 | 34.13 g | 29.18 g | 4.95 g | 25˚C | 0.99707 g/mL | 4.9645 mL |
Calculations:
Trial 1: 0.006 mL
Trial 2: -0.024 mL
Trial 3: 0.006 mL
Trial 4: -0.004 mL
Trial 5: 0.016 mL
(4.9545 mL + 4.9244 mL + 4.9545 mL + 4.9444 mL + 4.9645 mL) / 5 = 4.94849 mL
(0.006 mL - 0.024 mL + 0.006 mL - 0.004 mL + 0.016 mL) / 5 = 0.0112 mL
√((0.006 mL2 + (-0.024 mL)2 + 0.006 mL2 + (-0.004 mL)2 + 0.016 mL2) / (5 - 1)) = 0.0151 mL
Using the difference method, 0.50 x 1023 atoms of carbon and 0.52 x 1023 atoms of tin were transferred to a beaker. The average mass of one atom of carbon and tin was calculated to be 2.00 x 10-23 g and 1.96 x 10-23 g, respectively. This resulted in a ratio of the average mass of one atom of tin to carbon as 0.98:1, which did not match the correct theoretical value of 9.983:1.
The density of water at 25 degrees Celsius was found to be 0.9232 g/mL, while the literature value was 0.99707 g/mL. The calibration of a 5 mL pipette using five trials yielded an average volume of 4.94849 mL with a low average deviation of 0.0112 mL, indicating the accuracy of the experiment.
Experimental Investigation of Chemical Properties. (2024, Jan 02). Retrieved from https://studymoose.com/document/experimental-investigation-of-chemical-properties
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