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Stoichiometry of a Precipitation Reaction

Abstract: The purpose of the lab, Stoichiometry of a Precipitation Reaction, is to be able to calculate the amount of a second reactant we need to react with the reactant one. You must calculate the amount of the second reactant using stoichiometry to figure out what amount is needed. After the amount is calculated, you then can add it to the first reactant and it will give you a full reaction. To figure out what you need you have to use stoichiometry. My calculation for the second reactant was: 1.0g CaCl2*2H2O(1mol CaCl2*2H­2O/147g CaCl2*2H2O)(1mol Na2CO3/1mol CaCl2*2H2O)(106g Na2CO3/1mol Na2CO3) = 0.72g Na2CO3. The final, when its dried in the paper filtered weighed at 1.6 grams. Experiment and Observations: As I performed the…

Stoichiometry Precipitation

The calculations completed for this experiment include determining the amount of Na2CO3 needed to do a full reaction. This was calculated through stoichiometry calculations: Molar mass was first calculated for CaCl2*2H2O Ca = 40.078g Cl2 = 35.453g*2 = 70.906g 2H2 = 1.00794g*4 = 4.03176g 2O = 15.9994g*2 = 31.9988g 40.078g + 70.906g + 4.03176g + 31.9988g = 147.01456g or 147.0 g CaCl2 1g CaCl2 * 2H2O x (1 mol CaCl2 *2H2O/147g CaCl2 *2H2O) = 0.0068 mol of CaCl2*2H2O Molar mass was then calculated for Na2CO3: Na2 = 22.9898g*2 = 45.9796g C = 12.0107g O3 = 15.9994g*3 = 47.9982g 45.9796g + 12.0107g + 47.9982g = 105.9885g or 105.99g Na2CO3 Then using the molar mass of Na2CO3 and the 0.0068 mol of…

Stoichiometry of a Precipitation Reaction

Abstract: In this experiment Stoichiometry of a Precipitation Reaction, the main objectives were to use stoichiometry to calculate the theoretical yield of CaCO3 that precipitates from the reaction between Calcium chloride, Dihydrate and Sodium carbonate, and then compare that value to the actual yield. In order to do this accurately, we must be able to measure the products and reactants with accuracy. The last objective of this experiment is to calculate the percent yield of the product produced. When 1.0 g of Calcium chloride was mixed with 0.80 g of sodium carbonate, it produced 0.70 g calcium carbonate, which was very close to the theoretical yield of 0.68 g. Experiment and Observation: The first step in this experiment was to…