For this assignment the following in instructions are to complete and review the example of how complete the mat required for the assignment. To solve the problem 90 on page 304 of Elementary and Intermediate Algebra and to be sure that all steps of the squaring of the binominal and multiplication along with any simplification that might be used. Evaluate the polynomial resulting from step 1 using:

P= $200 and R=10%, and

Also with

P=5670 and R= 3.5%

Complete problem 70 on 311 page on Elementary and Intermediate Algebra show all steps of the division then incorporate words like foil, like terms, descending order, dividend, and divisor.

Problem #1

P (1+r/2)2

P [(1+r/2)*(1+ r/2)]

P [1 + r/2 +r/2 + r2 /4]

P (1+ r + r2/4) Let P + $200 and R = 10%

Convert 10% to a decimal which is 10/100 = .1

200* (1 + .1 + .12 /4)

200 + (200* .1) + (200 * .01/4) =

200+ 20+ .5 =

220.5

So you would make 20.5 dollars in the first year and the second year your

total account balance would be $ 243.10

Problem #2

Let P = 5670 and r = 3.5 %

Convert 3.5 % to a decimal 35/1000 = .035

P (1 + r +r2 /4)

5670* (1 + .035 + .03/4 52)

5670 + (5670 * .035) + (5670 * .00123/4) =

5670 + 198.45+1.74 = 5870.19

Problem #3

In this problem we follow the rules of normal division and exponents division Since the exponent in the divisor -3 xs is positive we will subtract on x from x 3 and that will become x2. So, now that we have 3×2 the process is the same with the entire exponent in the equation. (-9×33 +3×2- 15) / (-3x)

(-9×3/-3x) + (3x/-3x) – (15x/-3x)

3×2 –x +5

This equation cannot be Foil, because it is a quadratic equation.