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# Assuming that the distribution Essay

1. Assuming that the distribution is normal for weight relative to the ideal and 99% of the male participants scored between (–53.68, 64.64), where did 95% of the values for weight relative to the ideal lie? Round your answer to two decimal places. x=5.48, SD=22.93

5.48+1.96(22.93) = 170.5992
5.48-1.96(22.93)=80.7136
(80.71,170.60)

2. Which of the following values from Table 1 tells us about variability of the scores in a distribution? c. 22.57

3. Assuming that the distribution for General Health Perceptions is normal, 95% of the females’ scores around the mean were between what values? Round your answer to two decimal places. x=39.71, SD=25.46

39.71+1.96(25.46) = 89.6116
39.71-1.96(25.46) = -10.1916
(-10.19, 89.61)

4. Assuming that the distribution of scores for Pain is normal, 95% of the men’s scores around the mean were between what two values? Round your answer to two decimal places. x=52.53, SD=30.90
52.53+1.96(30.90) = 113.094
52.53-1.96(30.90) = -8.034
(-8.03, 113.09)

5. Were the body image scores significantly different for women versus men? Provide a rationale for your answer. Yes, body image scores were significantly higher for women (73.1 ± 17.0) than men (60.2 ± 17.0).

6. Assuming that the distribution of Mental Health scores for men is normal, where are 99% of the men’s mental health scores around the mean in this distribution? Round your answer to two decimal places. x= 57.09, SD=23.72

57.09+2.58(23.72)= 118.2876
57.09-2.58(23.72)= -4.1076
(-4.11, 118.29)

7. Assuming that the distribution of scores for Physical Functioning in women is normal, where are 99% of the women’s scores around the mean in this distribution? Round your answer to two decimal places. X= 65.20, SD=29.79 65.20+2.58(29.79) = 142.0582

65.20-2.58(29.79) = -11.6582
(-11.66, 142.06)

8. Assuming that the distribution of scores is normal, 99% of HIV-positive body image scores around the mean were between what two values? Round your answer to two decimal places. Body image scores for Male x= 60.22, SD=16.98; Female x= 73.07, SD= 16.93 Male: 60.22+2.58(16.98)= 104.0284

60.22-2.58(16.98)= 16.4116
Female: 73.07+2.58(16.93)= 116.7494
73.07-2.58(16.93)= 29.3906
Male and Female HIV+ Body Image scores combined are between (16.41, 116.75)

9. Assuming that the distribution of scores for Role Functioning is normal, 99% of the men’s scores around the mean were between what values? Round your answer to two decimal places. x=50.00, SD=46.29

50.00+2.58(46.29)= 169.4282
50.00-2.58(46.29)=-69.4282
(-69.43,169.43)

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